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Unreachable code in Java

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菜鸟教程小白 发表于 2022-5-23 13:43:00 | 显示全部楼层 |阅读模式 打印 上一主题 下一主题

I don't get what does "unreachable code" means ?

Here in the last line of my code double probabilityOfWin = wins / (wins + loses); it says unreachable code.

import java.util.Random;

 public class CrapsGame {
    public static final int GAMES = 9999;

public static void main(String[] args) {
    Random randomGenerator1 = new Random();
    Random randomGenerator2 = new Random();
    Random randomGenerator3 = new Random();
    Random randomGenerator4 = new Random();

    int dice1 = randomGenerator1.nextInt(6) + 1;
    int dice2 = randomGenerator2.nextInt(6) + 1;

    int comeoutSum = dice1 + dice2;
    int point = 0;

    // The comeout roll

    if (comeoutSum == 7 || comeoutSum == 12)
        System.out.println("wins");
    else if ( comeoutSum == 2 || comeoutSum == 3 || comeoutSum == 12)
        System.out.println("loses");
    else
         point = comeoutSum;

    int wins = 0;
    int loses = 0;


    while(GAMES <= 9999)
    {
        dice1 = randomGenerator3.nextInt(6) + 1;
        dice2 = randomGenerator4.nextInt(6) + 1;
        int sum = dice1 + dice2;

        if (sum == point)
            wins++;
        else if (sum == 7)
            loses++;
    }

    double probabilityOfWin = wins / (wins + loses);


}

}



Best Answer-推荐答案


This loop here:

while(GAMES <= 9999)
{
    ...
}

resolves to while (true) because the value of GAMES is never modified. So any code that comes after (in your case, double probabilityOfWin = wins / (wins + loses);) is deemed unreachable.

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